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x^2+95x+450=0
a = 1; b = 95; c = +450;
Δ = b2-4ac
Δ = 952-4·1·450
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7225}=85$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-85}{2*1}=\frac{-180}{2} =-90 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+85}{2*1}=\frac{-10}{2} =-5 $
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